6x^(2/3)-29x^(1/3)-5=0

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Solution for 6x^(2/3)-29x^(1/3)-5=0 equation: 


x in (-oo:+oo)

6*x^(2/3)-(29*x^(1/3))-5 = 0

6*x^(2/3)-29*x^(1/3)-5 = 0

t_1 = x^(1/3)

6*t_1^2-29*t_1^1-5 = 0

6*t_1^2-29*t_1-5 = 0

DELTA = (-29)^2-(-5*4*6)

DELTA = 961

DELTA > 0

t_1 = (961^(1/2)+29)/(2*6) or t_1 = (29-961^(1/2))/(2*6)

t_1 = 5 or t_1 = -1/6

t_1 = -1/6

x^(1/3)+1/6 = 0

1*x^(1/3) = -1/6 // : 1

x^(1/3) = -1/6

( -1/6 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 5

x^(1/3)-5 = 0

1*x^(1/3) = 5 // : 1

x^(1/3) = 5

x^(1/3) = 5 // ^ 3

x = 125

x = 125

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